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Posted By: Shade <wwight@wso.williams.edu> In Response To: Re: The Arithmetic Pattern...and Dial #3?? (Shade)
Date: 6 June 2001, 00:23
> Dial #2 was "45 5/7;"
> 2) In Dial #2, I used 5 numbers -- 67, 13, 48, 25 and 70 -- to get a matching
> number. I didn't use 3 numbers -- 3, 11 and 38. There's a bit of symmetry
> here, as far as 13 and 67, and 48 and 25, go.
That's good, but I think a better answer is that Dial #2 is 22.4 (7/10 of 32). It seems more intuitive to me, and it fixes the imperfect symmetry above because you can get 22.4 using 6 symmetrical numbers: ((67+13) * 70) / (25 * (48-38)) = 22.4. That leaves 3 and 11 as unused numbers.
If the the assumptions I'm making are correct, here's what we've got in all...
Dial #2: glyph value is 22.4, leftover numbers are 3, 11
Dial #3: glyph value is 22.5, leftover numbers are 0, 71
Dial #4: glyph value is 309, leftover numbers are 13, 37, 7
Dial #7: glyph value is 74, leftover numbers are 97, 83, 19, 18
Is this the right track, or are we shooting in the dark? Maybe there are multiple ways to get a match to our glyph solutions by using different symmetrical numbers. That would certainly blow a hole in this line of thought.
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