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Posted By: poena.dare #CP#g <hbo@mlcsmith.com> | Date: 2/12/02 1:34 p.m. |
In Response To: Workin' It (poena.dare #CP#g) From the PoA it looks like the ring has 24 'nipples' evenly spaced around the exterior of the ring. Using those, I come up with 1032 secs per revolution. (Hmmm, suspiciously close to 1024!) This is beginning to look nasty! a = v^2/r = (pi * 10,000,000 m / 1032 s)^2 / 5,000,000 m = 185 m/s^2 = 19 G !!! Oh dear... looks like the artificial gravity on Halo is a repulsive force that keeps you from being flattened! --- OK, lets change our assumptions: 1) The ring rotation rate as seen in the first level is WRONG.
rotation (secs) = pi * d / (a * r)^.5 = 3.15159 * 10,000,000 m / (9.8 m/s^2 * 5,000,000 s)^.5 = 4488 s, or about 1 hour, 15 minutes. In this scenario, standing outside the ring, the surface would crawl by at a modest 7,000 m/s. (15,658 miles per hour.) --- Someone else posted a question about the amount of materials that it would take to build Halo. While I can't figure out the mass, I can tell you the volume is about 700 billion cubic meters. A moonlet of the same density would be about 11 Km across. (19,864,354,834,000 bushels!) --- Notice the number of 7s cropping up? I ain't making this up! Feel free to check my math... it's only been 20 years since my last physics class. |
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