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Posted By: Neurotic <junkherethx@hotmail.com> In Response To: Re: It's a Bianary Operation 00000001 ? (Shade)
Date: 12 June 2001, 01:35
> given two functions, "foo" and "bar"
> foo [ bar (read "foo is a square subset of bar") if and only if
> foo(x) = bar(x) for all defined values of foo(x).
Heh. Off topic I know...but when I read that I just thought of the term "FUBAR", which reminds me of these puzzles. =P
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