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**Posted By: Tursas <iku-turso@home.com>Date: 13 June 2001, 16:20
**

In the solution to the 3rd glyph, two numbers are used; 0 and 6.

Perhaps these numbers are to play a different part in the solution to the problem. Perhaps also there are other numbers on the dials that require a similar special status. (Somebody jump in here and tell me if I've taken their idea.)

My whole idea is this: starting with the first glyph and moving clockwise around each succeeding glyph, discount two numbers. Eg. Starting with glyph 1, discount and put aside 37 and 19. Moving on to the second glyph, discount 48 and 25, then 0 and 6 from the third glyph, 22 and 113 from the fourth glyph, etc.

The nice thing about this theory is that all the points around the dials are discounted twice.

Perhaps the discounted numbers form the second password.

Thoughts?

**Are all the numbers valid? and a ring theory.**

Tursas -- 13 June 2001, 16:20**Oops.**

Tursas -- 13 June 2001, 16:25

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